Question

嗨，我读过很多论坛和网站，它们告诉您如何将图像上传到服务器，并且设法将其上传到服务器，我可以将文件上传到服务器上，但是存储文件名确实适用于以下示例而且我还需要创建一个表单，以允许将更多数据输入数据库。我坚持这样做，因为之前已经做过很多PHP。我已经结束尝试不同的网站教程的尝试了，但没有成功，任何人都可以帮助我！我需要为我正在做的项目完成它。

我基本上是在尝试制作一个CMS，允许用户上传乐队成员的照片并存储有关他们的信息，以便可以将其显示在网页上以供公众查看。

我的桌子看起来像这样：

Field              Type             Null    Default     
id                 int(10)          No                   
nameMember         varchar(25)      No                   
bandMember         text             No                   
photo              varchar(30)      No                   
aboutMember        text             No                   
otherBands         text             No

我想要的表格将如下所示：

   <h1>Adding a new Band Member or Affiliate</h1>
      <form method="post" action="addMember.php" enctype="multipart/form-data">
       <p>
              Please Enter the Band Members Name.
            </p>
            <p>
              Band Member or Affiliates Name:
            </p>
            <input type="text" name="nameMember"/>
            <p>
              Please Enter the Band Members Position. Example:Drums.
            </p>
            <p>
              Member's Position:
            </p>
            <input type="text" name="bandMember"/>
            <p>
              Please Upload a Photo in gif or jpeg format. The file name should be named after the Members name. If the same file name is uploaded twice it will be overwritten!
            </p>
            <p>
              Photo:
            </p>
            <input type="file" name="filep" size=35 />
            <p>
              Please Enter any other information about the band member here.
            </p>
            <p>
              Other Member Information:
            </p>
<textarea rows="10" cols="35" name="aboutMember">
</textarea>
            <p>
              Please Enter any other Bands the Member has been in.
            </p>
            <p>
              Other Bands:
            </p>
            <input type="text" name="otherBands" size=30 />
            <br/>
            <br/>
            <input TYPE="submit" title="Add data to the Database" value="Add Member"/>
          </form>

该示例仅将图像上传到服务器，就是这样：

<?

if ($_POST["action"] == "Load")
{
$folder = "images/";

move_uploaded_file($_FILES["filep"]["tmp_name"] , "$folder".$_FILES["filep"]["name"]);

echo "
<p align=center>File ".$_FILES["filep"]["name"]."loaded...";

$result = mysql_connect("localhost", "******", "*****") or die ("Could not save image name

Error: " . mysql_error());

mysql_select_db("project") or die("Could not select database");
mysql_query("INSERT into dbProfiles (photo) VALUES('".$_FILES['filep']['name']."')");
if($result) { echo "Image name saved into database

"; }

}

?>

我必须使用的示例表格是这样的：

<form action=addMember.php method=post enctype="multipart/form-data">
<table border="0" cellspacing="0" align=center cellpadding="3" bordercolor="#cccccc">
<tr>
<td>File:</td>
<td><input type="file" name="filep" size=45></td>
</tr>
<tr>
<td colspan=2><p align=center>
<input type=submit name=action value="Load">
</td>
</tr>
</table>
</form>

PS：图像文件已打开，可以写入。