获取OpenCV映像类型的枚举名称(例如CV_32FC1)?
c++
image-processing
opencv
6
0

在OpenCV的C ++接口中,检查图像类型似乎很容易。如果您有图像cv::Mat img = cv::imread("someImage.xyz") ,则只需int theType = img.type()

但是,正如您期望的那样,调用img.type()只会给出一个整数,而不是一个枚举名称(例如CV_32FC1 )。

如果我知道OpenCV枚举的整数值,是否有一种简单的方法可以打印出枚举名称(例如CV_32FC1 )?

参考资料:
Stack Overflow
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遵循@Bob的建议,我编写了自己的函数来解决此问题。这里是:

// take number image type number (from cv::Mat.type()), get OpenCV's enum string.
string getImgType(int imgTypeInt)
{
    int numImgTypes = 35; // 7 base types, with five channel options each (none or C1, ..., C4)

    int enum_ints[] =       {CV_8U,  CV_8UC1,  CV_8UC2,  CV_8UC3,  CV_8UC4,
                             CV_8S,  CV_8SC1,  CV_8SC2,  CV_8SC3,  CV_8SC4,
                             CV_16U, CV_16UC1, CV_16UC2, CV_16UC3, CV_16UC4,
                             CV_16S, CV_16SC1, CV_16SC2, CV_16SC3, CV_16SC4,
                             CV_32S, CV_32SC1, CV_32SC2, CV_32SC3, CV_32SC4,
                             CV_32F, CV_32FC1, CV_32FC2, CV_32FC3, CV_32FC4,
                             CV_64F, CV_64FC1, CV_64FC2, CV_64FC3, CV_64FC4};

    string enum_strings[] = {"CV_8U",  "CV_8UC1",  "CV_8UC2",  "CV_8UC3",  "CV_8UC4",
                             "CV_8S",  "CV_8SC1",  "CV_8SC2",  "CV_8SC3",  "CV_8SC4",
                             "CV_16U", "CV_16UC1", "CV_16UC2", "CV_16UC3", "CV_16UC4",
                             "CV_16S", "CV_16SC1", "CV_16SC2", "CV_16SC3", "CV_16SC4",
                             "CV_32S", "CV_32SC1", "CV_32SC2", "CV_32SC3", "CV_32SC4",
                             "CV_32F", "CV_32FC1", "CV_32FC2", "CV_32FC3", "CV_32FC4",
                             "CV_64F", "CV_64FC1", "CV_64FC2", "CV_64FC3", "CV_64FC4"};

    for(int i=0; i<numImgTypes; i++)
    {
        if(imgTypeInt == enum_ints[i]) return enum_strings[i];
    }
    return "unknown image type";
}

我是否忘记在查询表中包含任何OpenCV图像类型?

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据我所知,这种功能在OpenCV中不存在。

我认为您最好编写自己的函数来获得这些功能。很多开关案例,但我想它能完成任务。枚举可以在这里找到。

编辑:

这是您可以用来提取类型的东西。我猜想可能有一种更有效的方法,但是我现在无法解决这个问题。

std::string getImageType(int number)
{
    // find type
    int imgTypeInt = number%8;
    std::string imgTypeString;

    switch (imgTypeInt)
    {
        case 0:
            imgTypeString = "8U";
            break;
        case 1:
            imgTypeString = "8S";
            break;
        case 2:
            imgTypeString = "16U";
            break;
        case 3:
            imgTypeString = "16S";
            break;
        case 4:
            imgTypeString = "32S";
            break;
        case 5:
            imgTypeString = "32F";
            break;
        case 6:
            imgTypeString = "64F";
            break;
        default:
            break;
    }

    // find channel
    int channel = (number/8) + 1;

    std::stringstream type;
    type<<"CV_"<<imgTypeString<<"C"<<channel;

    return type.str();
}
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